4x^2+13x-7=4

Solution for 4x^2+13x-7=4 equation:

4x^2+13x-7=4

We move all terms to the left:

4x^2+13x-7-(4)=0

We add all the numbers together, and all the variables

4x^2+13x-11=0

a = 4; b = 13; c = -11;
Δ = b2-4ac
Δ = 132-4·4·(-11)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{345}}{2*4}=\frac{-13-\sqrt{345}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{345}}{2*4}=\frac{-13+\sqrt{345}}{8}
$